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5 Number Summary Calculator
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The 5 number summary is a easy way to have the statistical idea. It consists of following 5 statistical percentiles:
  • Maximum = Largest number
  • Minimum = smallest number
  • Median = It is the value that is in between the largest and the smallest data
  • First quartile = It is the value that separates the 75% percent of the largest data from the 25% smallest data
  • Third quartile = It is the value that separates the 25% percent of the largest data from the 75% smallest data.
The 5 number summary Calculator is a online tool that tells about the statistics of the given data.Enter the given data in the block provided to get the values of maximum, minimum, median, 1st quarter and 3rd quarter instantly.
 

Steps for 5 Number Summary Calculator

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Step 1 :  

Set the given data in ascending order, note down the number of elements in the given data n and find the maximum and minimum value.



Step 2 :  

The mean is calculated using the formula
Median = $\frac{n+1}{2}$ term

The Upper quartile is given by
Q1 = $\frac{n+1}{4}$ term
The lower quartile is given by
Q3 = $\frac{3(n+1)}{4}$ term

Substitute the values in above formula and get the answer.



Problems on 5 Number Summary Calculator

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  1. Find the max, min, median and other percentiles for the following set of data: {34,35,46,57,8,67}.


    Step 1 :  

    The given set of data is {34,35,46,57,8,67} and the order is {8,34,35,46,57,67 }


    No of elements n = 6
    Minimum value = 8
    Maximum value = 67



    Step 2 :  

    The mean is calculated using the formula
    Median = $\frac{n+1}{2}$ = $\frac{6+1}{2}$  = 3rd and 4th term
    $\therefore$ Median = $\frac{35+46}{2}$ = 40.5

    The Upper quartile is given by
    Q1 = $\frac{n+1}{4}$
        = $\frac{6+1}{4}$
        = $\frac{7}{4}$
        = 1.75


    First quartile is the average of 1st and 2nd term, i.e. $\frac{8+34}{2}$ = $\frac{42}{2}$ = 21
    The lower quartile is given by
    Q3 = $\frac{3(n+1)}{4}$
         = 3 $\times$ 1.75
         = 5.25


    Third quartile is the average of 5th and 6th term, i.e. $\frac{57+67}{2}$ = $\frac{124}{2}$ = 62



    Answer  :  

    Hence No of elements n = 6, minimum value = 8, maximum value = 67, median = 40.5, first quartile, Q1 = 21, third quartile, Q3 = 62.



  2. Calculate the max, min, median and upper quartile for the following set of data: {4,6,7,5,3,4}.


    Step 1 :  

    The given set of data is {4,6,7,5,3,4} and the order is {3,4,4,5,6,7}
    No of elements n = 6
    Minimum value = 3
    Maximum value = 7



    Step 2 :  

    The mean is calculated using the formula
    Median = $\frac{n+1}{2}$ = $\frac{6+1}{2}$  = 3rd and 4th term
    $\therefore$ Median = $\frac{4+5}{2}$ = 4.5

    The Upper quartile is given by
    Q1 = $\frac{n+1}{4}$
         = $\frac{6+1}{4}$
         = $\frac{7}{4}$
         = 1.75


    First quartile is the average of 1st and 2nd term, i.e. $\frac{3+4}{2}$ = $\frac{7}{2}$ = 3.5
    The lower quartile is given by
    Q3 = $\frac{3(n+1)}{4}$
         = 3 $\times$ 1.75
         = 5.25.


    Third quartile is the average of 5th and 6th term, i.e. $\frac{6+7}{2}$ = $\frac{13}{2}$ = 6.5



    Answer  :  

    Hence No of elements n = 6, minimum value = 3, maximum value = 7, median = 4.5, first quartile Q1 = 3.5, third quartile Q3 = 6.5.



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