Ideal Gas Law Formula Formula:
General Gas Equation: PV = nRT
Pressure(P) = nRT / V
Volume(V) = nRT / P
Temperature(T) = PV / nR
Moles of Gas(n) = PV / RT
where,
P = Pressure,
V = Volume,
n = Moles of gas,
T = Temperature,
R = 8.314 J K-1 mol-1, ideal gas constant.
Step 2 :
State the equation you plan to use and plug in the values.
Find the volume from the 0.361 moles gas at 300kpa and 400K temperature?
Step 1 :Given that:
Pressure(P) = 300 kPa,
Moles of gas(n) = 0.361 moles,
Temperature(T) = 400K
Volume(V) = ?
Step 2 :Substitue the given values in the formula:
Volume(V) = nRT / P
V = (0.361 × 8.314 × 400) / 300 [Since R = 8.314 J K-1 mol-1]
V = 1200.541 / 300
V = 4.002L
Answer :Volume(V) = 4.002L
Find the temperature from the 360ml cylinder contaning 0.60 moles gas at 264kpa?
Step 1 :Given that:
Volume(V) = 360ml = 360 / 1000 = 0.36 L,
Moles of gas(n) = 0.60 mol,
Pressure(P) = 264 kPa
Temperature(T) = ?
Step 2 :Substitue the given values in the formula:
Temperature(T) = PV / nR
T = (264 x 0.36) / (0.60 x 8.314)
T = 95.04 / 4.9884
T = 19.052 K
Answer :Temperature(T) = 19.052 K
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