Below is given a default equation you can just see how the balancing reaction of that equation is done and equilibrium constant(Kc) is calculated.
Convert the given word equation into formula equation.
Step 2 :
To balance the given equation: first write the number of different atoms present on left hand side and right hand side of the equation and then add coefficients to balance the equation, so that we have the equal number of atoms of each element on both the reactant(left hand side) and product(right hand side) of the equation.
Step 3 :
To know the equilibrium constant(Kc) of the given chemical reaction. Use the formula: Kc = $\frac{[C]^{c} [D]^{d}}{[A]^{a} [B]^{b}}$
where a,b,c and d = are the numbers in front of the each substances in the chemical reaction
A and B = are the concentration of reactant.
C and D = are the concentration of product.
Find the equilibrium constant(Kc) for the chemical equation: Al + O2 -> Al2O3 ?
Step 1 :Given chemical equation: Al + O2 -> Al2O3
Step 2 :Atoms on:
Reactants side Products side
4 x 1---------Al--------2 x 2 = 4
3 x 2---------O--------3 x 2 = 6
4Al + 3O2 -> 2Al2O3
Step 3 :Equilibrium constant(Kc) = $\frac{[Al_{2}O_{3}]^{2}}{[Al]^{4} [O_{2}]^{3}}$
Answer :Balanced equation: 4Al + 3O2 -> 2Al2O3
Equilibrium constant(Kc) = $\frac{[Al_{2}O_{3}]^{2}}{[Al]^{4} [O_{2}]^{3}}$
Find the equilibrium constant(Kc) for the chemical equation: H2 + I2 -> HI ?
Step 1 :Given chemical equation: H2 + I2 -> HI
Step 2 :Atoms on:
Reactants side Products side
2---------I--------1 x 2 = 2
2--------H--------1 x 2 =2
H2 + I2 -> 2 HI
Step 3 :Equilibrium constant(Kc) = $\frac{[HI]^{2}}{[H_{2}] [I_{2}]}$
Answer :Balanced equation: H2 + I2 -> 2 HI
Equilibrium constant(Kc) = $\frac{[HI]^{2}}{[H_{2}] [I_{2}]}$
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