Equivalent Weight Calculator

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**$Equivalent\ weight\ of\ acid = \frac{Molecular\ weight\ of\ acid}{Basicity\ of\ acid}$****$Equivalent\ weight\ of\ base = \frac{Molecular\ weight\ of\ base}{Acidity\ of\ base}$**

**Step 1 :**

**Step 2 :**

Equivalent weight of a substance depends upon the nature of chemical reaction in which the substance takes part. The chemical equivalent with reference to some standard is known as equivalent weight. Equivalent weight of hydrogen is taken as unity.

Equivalent weight of an element is defined as the number of parts by weight of it that combine or displace one part by weight of hydrogen or 8 parts by weight of oxygen or 35.5parts by weight of chlorine.

The Equivalent weight of acid or base is calculated by the given formula.

Read the problem carefully and list the values given.

Substitute the values in the corresponding formula to find out the equivalent weight.

$Equivalent\ weight\ of\ acid = \frac{Molecular\ weight\ of\ acid}{Basicity\ of\ acid}$

$Equivalent\ weight\ of\ base = \frac{Molecular\ weight\ of\ base}{Acidity\ of\ base}$

How many grams of H

_{3}PO_{4}are there is 0.3gm-equivalent of H_{3}PO_{4}, assuming complete neutralization?**Step 1 :**Formula weight of H

_{3}PO_{4}= 98.024

Basicity of H

_{3}PO_{4}= 3**Step 2 :**Substitute the values in the corresponding formula.

$Equivalent\ weight\ of\ acid = \frac{Molecular\ weight\ of\ acid}{Basicity\ of\ acid}$

$Equivalent\ weight\ of\ acid = \frac{98.024}{3}$

$Equivalent weight of acid = 32.674

1 gm equivalent of H

_{3}PO_{4}= 32.674gm

So 0.3 gm-equialent of H

_{3}PO_{4}= 32.674 $\times$ 0.3

= 9.802 gm of H

_{3}PO_{4}**Answer :**The equivalent weight of the given acid H

_{3}PO_{4}=**32.674gm**0.12375 gm of KOH neutralizes exactly 0.624gnm of an acid. Calculate the weight of the acid in 1-gm equivalent of the acid.

**Step 1 :**Formula weight of KOH =56.108

Acidity of KOH = 1

**Step 2 :**Substitute the values in the corresponding formula.

$Equivalent\ weight\ of\ base = \frac{Molecular\ weight\ of\ base}{Acidity\ of\ base}$

$Equivalent\ weight\ of\ base = \frac{56.108}{1}$

$Equivalent weight of base = 56.108

0.12375 gm of KOH = 0.624 gm of the acid

So 56.108 gm of KOH = $\frac{0.624 \times 56.108}{0.12375}$ gm of the acid

= 28.278 gm of the acid = 1 gm equivalent of the acid.

that is 1 gm equivalent of the acid = 28.278 gm of the acid

**Answer :**The equivalent weight of the given base KOH =

**56.108gm**