P $\propto$ T
Let Pi be the initial pressure of a gas at temperature Ti and Pf is the final pressure at temperature Tf.
Then Gay Lussac's law is given as:
$\frac{P_{i}}{T_{i}}$ = $\frac{P_{f}}{T_{f}}$.
Gay Lussac's law Calculator calculates either Pi, Pf, Ti or Tf if any of the three quantities are given.
Read the problem and List out the given quantities.
Step 2 :
Use the formula:
$\frac{P_{i}}{T_{i}}$ = $\frac{P_{f}}{T_{f}}$.
Substitute the given quantities in the above formula to get the desired quantity.
If initial temperature of a gas is 35oC at initial pressure 600 Pascal, Calculate final pressure if final temperature is 40oC?
Step 1 :given: Ti = 35oC,
Tf = 40oC,
Pi = 600 Pascal,
Pf = ?
Step 2 :Using the formula:
Pf = Tf $\times$ $\frac{P_{i}}{T_{i}}$
= 40 $\times$ $\frac{600}{35}$
= 685.71 Pascal.
Answer :The Final pressure is Pf = 685.71 Pascal.
If the gas molecules are moving inside a box with a initial pressure of 100 pascal and has a initial temperature of 20oC. Calculate the final temperature if final pressure is 105 pascal?
Step 1 :given: Ti = 20oC,
Tf = ?
Pi = 100 Pascal,
Pf = 105 Pascal.
Step 2 :$\frac{P_{i}}{T_{i}}$ = $\frac{P_{f}}{T_{f}}$.
Using the formula:
Tf = Pf $\times$ $\frac{T_{i}}{P_{i}}$
= 105 $\times$ $\frac{293}{100}$
= 307.65 K.
Answer :The final temperature Tf = 305.65 K.