Read the given problem and observe the given quantities.
Use the Gibbs free energy formula:
G = H + A - U
where G = Gibbs free energy,
H = Enthalpy,
A = Helmotz free energy and
U = Internal energy of the system.
Substituting the given values in the formula, we get the answer.
Calculate the Gibbs free energy of the following reaction:
C6H12O6 + 6O2 ----> 6CO2(g) + 6H2O(g)
If Enthalpy is - 2540 KJ, Helmoltz free energy A is 1000 J and Internal energy is 20 J.
Given: Enthalpy H = - 2540 KJ,
Helmoltz free energy A = 1000 J,
Internal energy U = 20 J
G = H + A - U
= - 2540 $\times$ 103 + 1000 - 20
= - 2539 KJ.
The Gibbs free energy is - 2539 KJ.
Find the Helmoltz free energy of the reaction:
4 NH3 + OH --> HNO3 + OH.
If Enthalpy is - 21.3 J, Gibbs free energy is - 35 J and Internal energy is 10 J.
Given: Enthalpy H = - 21.3 J,
Gibbs free energy G = - 35 J,
Internal energy U = 10 J
Helmoltz free energy A = ?
G = H + A - U
=> A = G - H + U
= - 35 - (- 21.98) + 10
= - 3.08 J.
The Helmoltz free energy A is - 3.08 J.