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Grams to Atoms Calculator
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The fundamental unit in the SI and GCS systems appears to be just a number. The mole is the unit for quantity whether atoms, molecules, ions or other kinds of particles. It is not possible to convert the given substance in grams to atoms. It should be carried out in two steps.

  • Convert the given grams into moles.
$\frac{Atoms}{Avogadro\ number}$ = moles
  • Then convert the moles into atoms.
Moles $\times$ atomic mass (or) molar mass = grams (or) molecules
 

Steps for Grams to atoms Calculator

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Step 1 :  

Read the problem carefully and list the given values.



Step 2 :  

Substitute the values in the corresponding formula to obtain the conversion.


$\frac{Atoms}{Avogadro number}$ = moles


Moles $\times$ atomic mass (or) molar mass = grams or molecules



Problems on Grams to atoms Calculator

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  1. How many ethane (C2H6) molecules are in 150.0 grams of ethane?


    Step 1 :  

    Given data


    Ethaen = 150.0 grams



    Step 2 :  

    Convert the grams to moles.


    150.0g C2H6 $\times \frac{1\ mole\ C_{2}H_{6}}{30.08\ g}$


    Convert from moles particles


    150.0g of C2H6 $\times \frac{1\ mole\ C_{2}H_{6}}{30.08g} \times \frac{6.022 \times 10^{23}\ molecules}{1\ mole}$ = 3.003 $\times$ 1024molecules.



    Answer  :  

    The answer is 3.003 $\times$ 1024molecules of ethane present in 150.0 grams of ethane.



  2. A certain sample of ethane C2H6 contained 7.5 $\times$ 1024 atoms of hydrogen. How many grams of ethane did the sample contain?


    Step 1 :  

    Given data


    C2H6 contains 7.5 $\times$ 1024 atoms of hydrogen



    Step 2 :  

    Convert atoms of hydrogen to moles of hdrogen


    7.5 $\times 10^{24}$ H atoms $\times \frac{1\ mole\ H}{6.022 \times 10^{23}\ atoms}$


    Convert from moles of hydrogen atoms to moles of ethane molecules.


    7.5 $\times 10^{24}$ H  atoms $ \times \frac{1\ mole\ H}{6.022 \times 10^{23}\ atoms} \times \frac{1\ mole\ ethane\ molecules}{6\ moles\ of\ H\ atoms}$


    Convert from moles of ethane to grams of ethane


    7.5 $\times 10^{24}$ H atoms $\times \frac{1\ mole\ H}{6.022 \times 10^{23}\ atoms} \times \frac{1\ mole\ ethane\ molecules}{6\ moles\ of\ H\ atoms} \times \frac{30.08g}{1\ mole\ C_{2}H_{6}}$ = 62g ethane



    Answer  :  

    The answer is the sample contains 62g of ethane.



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