Henry's constant kH with different units are given below in the table which helps in doing the manual calculations.
| Element | Henry Constant kH in $\frac{L atm}{mol}$ | Henry Constant kH in atm |
| O2 | 769.23 | 4.259 $\times$ 104 |
| H2 | 1282.05 | 7.099 $\times$ 104 |
| Co2 | 29.41 | 0.163 $\times$ 104 |
| N2 | 1639.34 | 9.077 $\times$ 104 |
| He | 2702.7 | 14.97 $\times$ 104 |
| Ne | 2222.22 | 12.3 $\times$ 104 |
| Ar | 714.28 | 3.955 $\times$ 104 |
| Co | 1052.63 | 5.828 $\times$ 104 |
Read the given problem and list out the given quantities.
There are two formulas to Calculate the partial pressure p
If Concentration of the solute is given use the formula
p = kH C
Where kH = Henry's law Constant,
C is the Concentration of the Solute.
If mole fraction of the solute is given then
p = kH x
Where kH = Henry's law Constant
x = Mole fraction of the Solute.
Substituting the values in the formula, we get the answer.
Find the Partial pressure of N2 containing 0.75 mol in a given mixture?
Given: Concentration of solute C = 0.75 mole
Henry Constant for mole fraction for N2, kH = 9.077 $\times$ 104 atm.
Since the Concentration of the solute is given we use the formula:
p = kH C
= 9.077 $\times$ 104 $\times$ 0.75
= 6807.75 atm.
The Partial pressure for N2 is 6807.75 atm.
Find the Partial pressure of Ne having mole fraction of 0.12 in a given mixture?
Given: Mole fraction, x = 0.12
Henry Constant for mole fraction for Ne, kH = 12.3 $\times$ 104 atm.
If mole fraction of the solute is given then
p = kH x
= 12.3 $\times$ 104 $\times$ 0.12
= 14760 atm.
The Partial pressure for Ne is 14760 atm.
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