To get the best deal on Tutoring, call 1-855-666-7440 (Toll Free)
Top

Radioactive Decay Calculator
Top
In 1896 Becquerel discovered uranium radioactivity and with the Curies opened the door to the nucleus of the atom. Soon after three types of decay were established. They are $\alpha$, $\beta$ and $\gamma$ decay. Radioactive decay phenomena continue to provide us with us many important messages.

The radioactive decay is calculated by using the formula.

$A = A_{o}e^\left (\frac{-0.693t}{T{\frac{1}{2}}} \right)$

Although the radioactive decay constants are independent of temperature and pressure, the retention of the radiogenic daughter in a mineral depends strongly on temperature.

Below is given a default isotope, you can see how the half life is calculated.


 

Steps for Radioactive Decay Calculator

Back to Top
Step 1 :  

Read the problem and list the given values.



Step 2 :  

Enter the isotopes in the first calculator and find out the half life value.



Step 3 :  

Substitute the value of half life and the given values in the formula to find out the radioactive decay.


$A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$



Problems on Radioactive Decay Calculator

Back to Top
  1. Calculate the radioactive decay for the isotope Actinium 227 whose initial activity is 4.5 and the decay time is 0.25sec?


    Step 1 :  

    Given data


    Initial activity (Ao) = 4.5


    Decay time (t) = 0.25sec



    Step 2 :  

    The half life value for the Actinium 227 isotopes is calculated as 21.77 years.


    T1/2 = 21.77 years



    Step 3 :  

    Substitute all the values in the corresponding formula.


    $A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$


    $A = 4.5 e^\frac{-0.693(0.25)}{21.77}$


    A = 4.46 years



    Answer  :  

    The final activity is A = 4.46 years



  2. Calculate the final radioactivity of Cobalt 57 isotope whose initial activity is 6.8 and the decay time is 0.86.


    Step 1 :  

    Given data


    Initial activity (Ao) = 6.8


    Decay time (t) = 0.86



    Step 2 :  

    The half life value for the Cobalt 57 isotopes is calculated as 270 days.


    T1/2 = 270 days



    Step 3 :  

    Substitute all the values in the corresponding formula.


    $A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$


    $A = 6.8 e^\frac{-0.693(0.86)}{270}$


    A = 6.78



    Answer  :  

    The final radioactive decay is A = 6.78



*AP and SAT are registered trademarks of the College Board.