Below is given a default isotope, you can see how the half life is calculated.
Read the problem and list the given values.
Step 2 :
Enter the isotopes in the first calculator and find out the half life value.
Step 3 :
Substitute the value of half life and the given values in the formula to find out the radioactive decay.
$A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$
Calculate the radioactive decay for the isotope Actinium 227 whose initial activity is 4.5 and the decay time is 0.25sec?
Step 1 :Given data
Initial activity (Ao) = 4.5
Decay time (t) = 0.25sec
Step 2 :The half life value for the Actinium 227 isotopes is calculated as 21.77 years.
T1/2 = 21.77 years
Step 3 :Substitute all the values in the corresponding formula.
$A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$
$A = 4.5 e^\frac{-0.693(0.25)}{21.77}$
A = 4.46 years
Answer :The final activity is A = 4.46 years
Calculate the final radioactivity of Cobalt 57 isotope whose initial activity is 6.8 and the decay time is 0.86.
Step 1 :Given data
Initial activity (Ao) = 6.8
Decay time (t) = 0.86
Step 2 :The half life value for the Cobalt 57 isotopes is calculated as 270 days.
T1/2 = 270 days
Step 3 :Substitute all the values in the corresponding formula.
$A = A_{o}e^\frac{-0.693t}{T{\frac{1}{2}}}$
$A = 6.8 e^\frac{-0.693(0.86)}{270}$
A = 6.78
Answer :The final radioactive decay is A = 6.78