Specific Heat Calculator

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**Step 1 :**

**Step 2 :**

Amount of heat, required to raise the temperature of a substance by a certain amount, depends on the properties of the substance and this amount of heat varies from substance to substance. Specific heat is essentially a measure of how thermally insensitive a substance is to the addition of energy. **Specific Heat Calculator** will help us to calculate the specific heat of different substances.

“Specific heat c of a substance is defined as the heat capacity of the substance per unit mass of the substance.”

**Specific Heat Formula**

Specific Heat of the substance is

**c =** $\frac{Q}{m \Delta{T}}$

Where

c- Specific heat of the substances

Q- The energy given to the substance

m- Mass of the substances

$\Delta$T- Change in the temperature of the substance.

“Specific heat c of a substance is defined as the heat capacity of the substance per unit mass of the substance.”

Where

c- Specific heat of the substances

Q- The energy given to the substance

m- Mass of the substances

$\Delta$T- Change in the temperature of the substance.

Specific Heat Formula:

Specific Heat(c) = $\frac{Q}{m \Delta{T}}$

Quantity of Heat Needed(Q) = c $\times$ m $\times$ $\Delta{T}$

Mass of the Substance(m) = $\frac{Q}{c \Delta{T}}$

Change in the Temperature($\Delta{T}$) = $\frac{Q}{m \times c}$

Where

c- Specific heat of the substances

Q- The energy given to the substance

m- Mass of the substances

$\Delta$T- Change in the temperature of the substance.

State the equation you plan to use and plug in the values.

Calculate the specific heat of a substance which absorbs 4.6 joules of heat when its mass of 2.0 kg increases with respect to the change in temperature of 60$^{\circ}$C?

**Step 1 :**Given that:

Quantity of Heat Needed(Q) = 4.6 joules

Mass of the substances(m) = 2.0 kg

Change in Temperature($\Delta{T}$) = 60$^{\circ}$C

Specific Heat(c) = ?

**Step 2 :**We know that:

Specific Heat(c) = $\frac{Q}{m \Delta{T}}$

Specific Heat(c) = $\frac{4.6}{2.0 \times 60}$

Specific Heat(c) = 0.0383333333 J/kg.$^{\circ}$C

**Answer :**Specific Heat(c) = 0.0383 J/kg.$^{\circ}$C

Calculate the amount of heat required for a substance of mass 3.0kg, whose specific heat is 0.632 J/kg.$^{\circ}$C during the temperature difference of 50$^{\circ}$C?

**Step 1 :**Given that:

Specific Heat(c) = 0.632 J/kg.$^{\circ}$C

Mass of the substances(m) = 3.0 kg

Change in Temperature($\Delta{T}$) = 50$^{\circ}$C

Quantity of Heat Needed(Q) = ?

**Step 2 :**We know that:

Quantity of Heat Needed(Q) = c $\times$ m $\times$ $\Delta{T}$

Quantity of Heat Needed(Q) = 0.632 $\times$ 3.0 $\times$ 50

Quantity of Heat Needed(Q) = 94.8 joules

**Answer :**Quantity of Heat Needed(Q) = 94.8 joules