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Thermal Expansion Calculator
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As the temperature increases the body undergoes thermal expansion in length, area and volume. Here is a online tool to calculate the thermal expansion in length.
Thermal expansion Calculator is a online tool to calculate the linear expansion. You just have enter either 4 of these namely initial length L1, initial temperature T1, final temperature T2, coefficient of linear expansion $\alpha$ or linear expansion L to get the unknown quantity instantly.
 

Steps for Thermal Expansion Calculator

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Step 1 :  

Read the given problem and observe the given quantities



Step 2 :  

Use the formula


L = $\alpha$ L1 (T2 - T1)
Here L1 is initial length,
L is linear expansion,
T1 is initial temperature,
T2 is final temperature,
$\alpha$ is the coefficient of linear expansion of the material


Substitute the values in above formula and get the answer.



Problems on Thermal Expansion Calculator

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  1. A lead pipe is 60 m long at temperature 250C. If the hot water flows through it the temperature of pipe raises to 500C. Calculate the length of hot pipe if the linear expansion coefficient is 29 $\times$ 10-6 K-1.


    Step 1 :  

    Given:Initial Length L1 = 60 m,
    Initial temperature T1 = 250 C,
    Final temperature T2 = 500 C,
    Linear expansion coefficient $\alpha$ = 29 $\times$ 10-6 K-1



    Step 2 :  

    The Thermal exapansion is given by
    L = $\alpha$ $\times$ L1 (T2 - T1)
      = 29 $\times$ 10-6K-1 $\times$ 60 m (60 - 25)0 C
      = 43500 $\times$ 10-6 m
      = 0.0435 m.



    Answer  :  

    The thermal expansion L = 0.0435 m.



  2. A metal rod is measured at 150 C is 4 m long. If the temperature is raised to 40o C the rod length will be 4.5 m.Calculate the coefficient of linear expansion.


    Step 1 :  

    Given:Initial Length L1 = 4 m,
    Initial temperature T1 = 15o C,
    Final temperature T2 = 40o C,
    Linear expansion L = 0.5 m



    Step 2 :  

    The Thermal exapansion is given by
    L = $\alpha$ $\times$ L1 (T2 - T1)

    Hence thermal coefficient $\alpha$ is
    $\alpha$ = $\frac{L}{L_1 (T_2 - T_1)}$
        = $\frac{0.5}{4 (40^o C - 15^o C)}$
        = 0.005$\times$ 10-6o C-1.



    Answer  :  

    Coefficient of thermal expansion $\alpha$ = 0.005$\times$ 10-6o C-1.



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