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Inductance Calculator
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Its known that inductance (L) is the opposing change in current. Lets take coil wounded by the wire the resisting force that acts in a coil of wire due the current flow leads to the emf.

So the inductance is given by
L = $\frac{\mu N^2 A}{l}$Where $\mu$ is the core material permeability,
N is the no of turns the coil wire has,
A is the core area,
l is the average coil length.

Inductance Calculator is a online tool to calculate any unknown quantity of these inductance (L), core material permeability ($\mu$), no of turns (N), core area (A), average coil length (l) if any four of these are known.

## Steps for Inductance Calculator

Step 1 :

Read the given problem and observe the quantities given

Step 2 :

Use the formula

L = $\frac{N^2 \mu A}{l}$

Substitute the given values in above equation and calculate the unknown quantity.

## Problems on Inductance Calculator

1. ### A inductor coil has 600 turns of copper wire with core area 0.6 m2 and length 70 m with permeability 0.6.Calculate the self-inductance.

Step 1 :

Given: No of turns N = 600 turns,
Area A = 0.6 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 600^2 \times 0.6 m}{70 m}$
= 1851.4 Henry

Hence the inductance L of the coil is 1851.4 Henry.

2. ### A coiled wire has 320 turns having the diameter of 20 cm and an unstretched length of 29 cm. what is its self inductance?

Step 1 :

Given: No of turns N = 320 turns,
Area A = $\pi$ $\times$ r2 = 314.2 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 320^2 \times 314.2 m}{70 m}$
= 275777.8 Henry